###### Difficulty: Hard

This is a perfect problem to use the Plugging In Numbers (PIN) strategy.  To use this strategy, simply choose a number (not usually 0 or 1) to plug in for x.  Plug the number into the given expression and then plug it into each of the answer choices to see which one (or ones) match.  A word of caution with this method: Always make sure to check EVERY answer choice.  Sometimes, more than one will work and you will need to try a different number in order to determine which answer choice is correct.

Ex. Choose x = 2

$\frac{6(2)-5}{2+2}$ = $\frac{12-5}{4}$ = $\frac{7}{4}$

A)  $\frac{6-5}{2}=\frac{1}{2}\neq&space;\frac{7}{4}$

B)  $6-\frac{5}{2}$ = $6(\frac{2}{2})-\frac{5}{2}$ = $\frac{12}{2}-\frac{5}{2}$ = $\frac{7}{2}\neq&space;\frac{7}{4}$

C)  $6-\frac{5}{2+2}$ = $6-\frac{5}{4}$ = $6(\frac{4}{4})-\frac{5}{4}$ = $\frac{24}{4}-\frac{5}{4}$ = $\frac{19}{4}$ $\neq&space;\frac{7}{4}$

D) $6-\frac{17}{2+2}$ = $6-\frac{17}{4}$ = $6(\frac{4}{4})-\frac{17}{4}$ = $\frac{24}{4}-\frac{17}{4}$ = $\frac{7}{4}$ . Yay!!